Dev-c++ Program Ends After Input
May 04, 2010 The problem is that I so badly need to know how I can end my program in C, like I can give the user (Y/N) option, if they want to continue using the program or not. This is the code I've been working on, I need your corrections, guys. Move to EarthLink. When i execute a program using Dev-C the program will not show the end result after entering input; it will just exit the display screen. C: If and Else Statements. So we've learnt how to collect basic data from the user, but wouldn't it be useful if we could do different things depending on what the user typed in? Well this happens to be a very core concept of computer programming, and we can do exactly as previously described with these things called 'if' statements.
Here's a functioning program using signals that you can use as a model. Press Ctrl-C for Snooze. After five alarms, it exits. If you override the traditional Ctrl-C like I have, you should make sure that the program doesn't go on forever (hence the loop of five). You can make this program much more elaborate, but this is the basic idea. C: If and Else Statements. So we've learnt how to collect basic data from the user, but wouldn't it be useful if we could do different things depending on what the user typed in? Well this happens to be a very core concept of computer programming, and we can do exactly as previously described with these things called 'if' statements. There may exist some loops which can iterate or occur infinitely. These are called Infinite Loop. These loops occur infinitely because their condition is always true. We can make an infinite loop by leaving its conditional expression empty (this is one of the many possible ways). When the conditional expression is empty, it is assumed to be true. Apr 30, 2019 For example, after entering into the cin statement, we need to input a character array or string. So we need to clear the input buffer, otherwise it will occupy the buffer of previous variable. By pressing the “Enter” key after the first input, as the buffer of previous variable has space to hold new data, the program skips the following.
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The cin.ignore() function is used which is used to ignore or clear one or more characters from the input buffer.
To get the idea about ignore() is working, we have to see one problem, and its solution is found using the ignore() function. The problem is like below.
Sometimes we need to clear the unwanted buffer, so when next input is taken, it stores into the desired container, but not in the buffer of previous variable. For example, after entering into the cin statement, we need to input a character array or string. So we need to clear the input buffer, otherwise it will occupy the buffer of previous variable. By pressing the “Enter” key after the first input, as the buffer of previous variable has space to hold new data, the program skips the following input of container.
Example
Output
There are two cin statements for integer and string, but only number is taken. When we press enter key, it skips the getLine() function without taking any input. Sometimes it can take input but inside the buffer of integer variable, so we cannot see the string as output.
Now to resolve this issue, we will use the cin.ignore() function. This function is used to ignore inputs upto given range. If we write the statement like this −
Then it ignores input including the new line character also.
Example
Output
Dev-c Program Ends After Input Tool
Hello, I'm still a huge beginner in C++ and while i spent hours trying to find a solution to this problem i came to this forum pretty often and I thought it'd be a good idea if I try to ask about my problem. (If you notice anything that can be done better I'd be more than happy to hear an criticism, advice, or lesson about coding). I just wanted to try a little project on my own outside of my C++ class and I wanted to make a timer for myself (since i always end up losing my sense of time on the computer haha), Everything was going fine until i found the urge to make a Snooze and shutdown available while my program continuously plays a beep (Sort of like an alarm clock). Obviously Im stuck at being able to input something while the beep is going on. I don't even know if its possible since If i do cin>> in the loop itll only beep once before it waits for input and if i dont itll just never stop looping. Line 40 and down is me trying to use getch() (I read up about inputting without the prompting of enter, so i was hoping it would somehow work) but it doesnt work the way I want it to.
Edit: i use dev-cpp btw :P (If theres a better program/compiler out there id also be glad to hear about that.)
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VernonDozier2,218
Looks like your program got cut off, but I think the general gist is this. Programs like this are sequential. One thing happens at a time. You are either beeping, calculating, waiting for input, display, calculating, whatever. Two things can't happen at the same time in most programs.
If you want to be able to beep and accept input at the same time, you need a separate process and/or separate threads. That can get complex. I am not too familiar with the 'system' command. It's generally frowned on, but it may be a blunt instrument that can do the job in your case. I don't know.
But the right way would be to have a process/thread (there are pros and cons to each) that is spawned when the alarm goes off and which is run separately. When snooze is hit, you kill that beep process. Looks like you're in Windows. I know nothing about how to create threads/processes in Windows C++, and to be fair, not much more on ho to do it in Linux.
Dev-c Program Ends After Input Pdf
But I think that what you are trying to do cannot be done in one process containing one thread.